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How many of the following compounds woul...

How many of the following compounds would give Iodoform test
(1) `s CH_(3) - CO - CH_(2) - CO - OCH_(3)` (2) `C_(6) H_(5) - CO - CH_(2) - CO - C_(6)H_(5)`
(3) `CH_(3) - CHCl - CH_(2) - CH_(3)` (4) `CH_(3) - CHNH_(2) - CH_(3)`
(5) `CH_(3) - CO - CH_(2)I` (6) `CH_(3) - CO - O - CO - CH_(3)`
(7) `CH_(3) - CO - O - CH_(3)` (8) `CH_(3) - CO - Cl`
(9) `CH_(3) - CHOH - CH_(2) - CH_(3)` (10) `CH_(3) - CO - CH_(2) - CHOH - CH_(3)`

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The correct Answer is:
To determine how many of the given compounds would give a positive iodoform test, we need to identify which of these compounds contain a methyl ketone group (CH3C=O) or a secondary alcohol that can be oxidized to a methyl ketone. The iodoform test is positive for compounds that contain these functional groups. ### Step-by-Step Solution: 1. **Identify the Compounds**: - (1) `s CH₃ - CO - CH₂ - CO - OCH₃` - (2) `C₆H₅ - CO - CH₂ - CO - C₆H₅` - (3) `CH₃ - CHCl - CH₂ - CH₃` - (4) `CH₃ - CHNH₂ - CH₃` - (5) `CH₃ - CO - CH₂I` - (6) `CH₃ - CO - O - CO - CH₃` - (7) `CH₃ - CO - O - CH₃` - (8) `CH₃ - CO - Cl` - (9) `CH₃ - CHOH - CH₂ - CH₃` - (10) `CH₃ - CO - CH₂ - CHOH - CH₃` 2. **Analyze Each Compound**: - **Compound (1)**: `s CH₃ - CO - CH₂ - CO - OCH₃` - Contains a methyl ketone (CH₃C=O). **Positive** - **Compound (2)**: `C₆H₅ - CO - CH₂ - CO - C₆H₅` - No methyl ketone or secondary alcohol. **Negative** - **Compound (3)**: `CH₃ - CHCl - CH₂ - CH₃` - Contains Cl instead of OH. **Negative** - **Compound (4)**: `CH₃ - CHNH₂ - CH₃` - Contains NH₂ instead of OH. **Negative** - **Compound (5)**: `CH₃ - CO - CH₂I` - Contains a methyl ketone (CH₃C=O). **Positive** - **Compound (6)**: `CH₃ - CO - O - CO - CH₃` - This is an ester. **Negative** - **Compound (7)**: `CH₃ - CO - O - CH₃` - This is also an ester. **Negative** - **Compound (8)**: `CH₃ - CO - Cl` - Contains a methyl ketone (CH₃C=O). **Positive** - **Compound (9)**: `CH₃ - CHOH - CH₂ - CH₃` - Contains a secondary alcohol that can be oxidized to a methyl ketone. **Positive** - **Compound (10)**: `CH₃ - CO - CH₂ - CHOH - CH₃` - Contains a methyl ketone (CH₃C=O). **Positive** 3. **Count the Positive Results**: - Positive for compounds: (1), (5), (8), (9), (10) - Total positive results = 6 ### Final Answer: The total number of compounds that would give a positive iodoform test is **6**. ---
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C_(6)H_(5)-CH=CH-CO-CH_(3)

CH_(3)-CO-CO-CH_(2)CH_3

Amongest the following maximum number of compounds which give iodoform test are CH_(3)CONH_(2),CH_(3)COCl, CHCOOH,(CH_(3)CO)_(2) C_(6)H_(5)COCH_(3),C_(6)H_(5)CH_(2)CHO , C_(6)H_(5)(OH)CH_(3) C_(6)H_(5)CH_(2)CH_(2)OH,(CH_(3))_(2)C=CHCOCH_(3) CH_(3)COCH_(2)COOC_(2)H_(5)

Arrange the following compounds in the increasing order of their boiling points: CH_(3)CH_(2)CH_(2)CHO, CH_(3)CH_(2)CH_(2)CH_(2)OH, H_(5)C_(2)-O-C_(2)H_(5),CH_(3)CH_(2)CH_(2)CH_(3)

The IUPAC name of the compound CH_(3) - CH( OCH_(3)) - CO - CH(CH_(3)) - O - CH_(2) -CH_(3) is :

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