Home
Class 11
PHYSICS
The angular velocity of a wheel increas...

The angular velocity of a wheel increases from 100 to 300 in 10 s. The number of revolutions made during that time is

A

600

B

1500

C

1000

D

2000

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of revolutions made by the wheel as its angular velocity increases from 100 to 300 in 10 seconds, we can follow these steps: ### Step 1: Convert Angular Velocities to Radians per Second The initial angular velocity \( \omega_1 \) is given as 100 revolutions per minute (rpm). We need to convert this to radians per second. \[ \omega_1 = 100 \text{ rpm} = 100 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{200\pi}{60} = \frac{10\pi}{3} \text{ radians/second} \] The final angular velocity \( \omega_2 \) is 300 rpm. \[ \omega_2 = 300 \text{ rpm} = 300 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{600\pi}{60} = 10\pi \text{ radians/second} \] ### Step 2: Calculate Angular Acceleration We can find the angular acceleration \( \alpha \) using the formula: \[ \alpha = \frac{\omega_2 - \omega_1}{t} \] Substituting the values: \[ \alpha = \frac{10\pi - \frac{10\pi}{3}}{10} = \frac{10\pi \left(1 - \frac{1}{3}\right)}{10} = \frac{10\pi \cdot \frac{2}{3}}{10} = \frac{2\pi}{3} \text{ radians/second}^2 \] ### Step 3: Calculate the Angular Displacement Now we can calculate the angular displacement \( \theta \) using the formula: \[ \theta = \omega_1 t + \frac{1}{2} \alpha t^2 \] Substituting the values: \[ \theta = \left(\frac{10\pi}{3}\right) \cdot 10 + \frac{1}{2} \cdot \left(\frac{2\pi}{3}\right) \cdot (10)^2 \] Calculating each term: \[ \theta = \frac{100\pi}{3} + \frac{1}{2} \cdot \frac{2\pi}{3} \cdot 100 = \frac{100\pi}{3} + \frac{100\pi}{3} = \frac{200\pi}{3} \text{ radians} \] ### Step 4: Convert Angular Displacement to Revolutions To find the number of revolutions, we divide the angular displacement by \( 2\pi \): \[ \text{Number of revolutions} = \frac{\theta}{2\pi} = \frac{\frac{200\pi}{3}}{2\pi} = \frac{200}{6} = \frac{100}{3} \approx 33.33 \] ### Final Answer The number of revolutions made during that time is approximately 33.33 revolutions. ---

To find the number of revolutions made by the wheel as its angular velocity increases from 100 to 300 in 10 seconds, we can follow these steps: ### Step 1: Convert Angular Velocities to Radians per Second The initial angular velocity \( \omega_1 \) is given as 100 revolutions per minute (rpm). We need to convert this to radians per second. \[ \omega_1 = 100 \text{ rpm} = 100 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{200\pi}{60} = \frac{10\pi}{3} \text{ radians/second} \] ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ROTATION

    DC PANDEY|Exercise Check point 9.2|20 Videos
  • ROTATION

    DC PANDEY|Exercise Check point 9.3|15 Videos
  • ROTATION

    DC PANDEY|Exercise (C) Chapter Exercises|39 Videos
  • RAY OPTICS

    DC PANDEY|Exercise Integer type q.|15 Videos
  • ROTATIONAL MECHANICS

    DC PANDEY|Exercise Subjective Questions|2 Videos

Similar Questions

Explore conceptually related problems

The angular speed of truck wheel is increased from 900rpm to 2460 rpm in 26 seconds.The number of revolutions by the truck engine during this time is "____________" . ( Assuming the acceleration to be uniform )

The angular velocity of a motor wheel changes from 180 rpm to 300 rpm in 4 seconds. Calculate the no. of revolutions does the engine make during this time.

Knowledge Check

  • The angular velocity of a wheel increases from 120 to 480 rpm in 10 s .The number of revolutions made during this time is

    A
    10
    B
    25
    C
    50
    D
    100
  • The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds How many revolutions does the engine make during this time ?

    A
    376
    B
    476
    C
    576
    D
    676
  • A wheel increases its speed from 60 rpm to 120 rpm in 10 s. Number of rotation made by it in 10 s is

    A
    10
    B
    15
    C
    25
    D
    20
  • Similar Questions

    Explore conceptually related problems

    A constant net torque equal to 20 N-m is exerted on a pivoted wheel for 8 sec, during which time the angular velocity of the wheel increases from zero to 100 re // min. The external torque is then removed and the wheel is brought to rest by friction in its bearings in 70 sec. Compute (a) the moment of inertia of the wheel about the rotation axis, (b) the friction torque(c)thetotal no. of revolutions made by the wheel in the70 sec time interval

    A flywheel rotates with a uniform angular acceleration. Its angular speed increases from 2pirad//s to 10pirad//s in 4 s . Find the number of revolutions in this period.

    The angular speed of a motor wheel is increases from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration of the motor wheel is,

    A grinding wheel attained a velocity of 20 rad/sec in 5 sec starting from rest. Find the number of revolutions made by the wheel.

    The angular speed of a motor wheel is increased from 120 rpm to 3120 rpm in 16 seconds. The angular acceleration of the motor wheel is