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The angular velocity of a wheel increas...

The angular velocity of a wheel increases from 100 to 300 in 10 s. The number of revolutions made during that time is

A

600

B

1500

C

1000

D

2000

Text Solution

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The correct Answer is:
To find the number of revolutions made by the wheel as its angular velocity increases from 100 to 300 in 10 seconds, we can follow these steps: ### Step 1: Convert Angular Velocities to Radians per Second The initial angular velocity \( \omega_1 \) is given as 100 revolutions per minute (rpm). We need to convert this to radians per second. \[ \omega_1 = 100 \text{ rpm} = 100 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{200\pi}{60} = \frac{10\pi}{3} \text{ radians/second} \] The final angular velocity \( \omega_2 \) is 300 rpm. \[ \omega_2 = 300 \text{ rpm} = 300 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{600\pi}{60} = 10\pi \text{ radians/second} \] ### Step 2: Calculate Angular Acceleration We can find the angular acceleration \( \alpha \) using the formula: \[ \alpha = \frac{\omega_2 - \omega_1}{t} \] Substituting the values: \[ \alpha = \frac{10\pi - \frac{10\pi}{3}}{10} = \frac{10\pi \left(1 - \frac{1}{3}\right)}{10} = \frac{10\pi \cdot \frac{2}{3}}{10} = \frac{2\pi}{3} \text{ radians/second}^2 \] ### Step 3: Calculate the Angular Displacement Now we can calculate the angular displacement \( \theta \) using the formula: \[ \theta = \omega_1 t + \frac{1}{2} \alpha t^2 \] Substituting the values: \[ \theta = \left(\frac{10\pi}{3}\right) \cdot 10 + \frac{1}{2} \cdot \left(\frac{2\pi}{3}\right) \cdot (10)^2 \] Calculating each term: \[ \theta = \frac{100\pi}{3} + \frac{1}{2} \cdot \frac{2\pi}{3} \cdot 100 = \frac{100\pi}{3} + \frac{100\pi}{3} = \frac{200\pi}{3} \text{ radians} \] ### Step 4: Convert Angular Displacement to Revolutions To find the number of revolutions, we divide the angular displacement by \( 2\pi \): \[ \text{Number of revolutions} = \frac{\theta}{2\pi} = \frac{\frac{200\pi}{3}}{2\pi} = \frac{200}{6} = \frac{100}{3} \approx 33.33 \] ### Final Answer The number of revolutions made during that time is approximately 33.33 revolutions. ---

To find the number of revolutions made by the wheel as its angular velocity increases from 100 to 300 in 10 seconds, we can follow these steps: ### Step 1: Convert Angular Velocities to Radians per Second The initial angular velocity \( \omega_1 \) is given as 100 revolutions per minute (rpm). We need to convert this to radians per second. \[ \omega_1 = 100 \text{ rpm} = 100 \times \frac{2\pi \text{ radians}}{1 \text{ revolution}} \times \frac{1 \text{ minute}}{60 \text{ seconds}} = \frac{200\pi}{60} = \frac{10\pi}{3} \text{ radians/second} \] ...
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