A wheel of radius 10 cm can rotate freely about its centre as shown in figure. A string is wrapped over its rim and is pulled by a force of 5.0 N. It is found that the torque produces an angular acceleration 2.0 `rad/s^2` in the wheel. Calculate the moment of inertia of the wheel.

Options

A. `0.25 "kg-m"^(2)`
B. `0.45 "kg-m"^(2)`
C. `0.15 "kg-m"^(2)`
D. `0.16 "kg-m"^(2)`

Answer

A

Explanation

Torque, `tau=I alpha`, Moment of inertia of wheel, `I = (tau)/(alpha)`
Moment of inertia of wheel,
`I=(5xx10xx10^(-2))/(2)"kg-m"^(2)=0.25 "kg-m"^(2)`.