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A wheel of radius 10 cm can rotate freel...

A wheel of radius 10 cm can rotate freely about its centre as shown in figure. A string is wrapped over its rim and is pulled by a force of 5.0 N. It is found that the torque produces an angular acceleration 2.0 `rad/s^2` in the wheel. Calculate the moment of inertia of the wheel.

A

`0.25 "kg-m"^(2)`

B

`0.45 "kg-m"^(2)`

C

`0.15 "kg-m"^(2)`

D

`0.16 "kg-m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Torque, `tau=I alpha`, Moment of inertia of wheel, `I = (tau)/(alpha)`
Moment of inertia of wheel,
`I=(5xx10xx10^(-2))/(2)"kg-m"^(2)=0.25 "kg-m"^(2)`.
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Knowledge Check

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