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Calculate difference between number of a...

Calculate difference between number of a `beta` particles emmited in the nuclear reaction
`""_(92)U""^(23)to""_(82)Pb""^(206)`

Text Solution

Verified by Experts

The correct Answer is:
2
No. of `alpha=(Ap-Ad)/4`,No. of `beta=2xxalpha-(Zp-Zd)`
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Knowledge Check

  • The total number of alphaandbeta particles emitted in the nuclear reaction ""_(92)^(238)Uto""_(82)^(214)Pb is

    A
    6
    B
    7
    C
    8
    D
    10

  • The number of beta- particles emitted in the following nuclear reaction is

    A
    Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion
    B
    Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion
    C
    Assertion is correct but Reason is incorrect
    D
    Assertion is incorrect but Reason is correct

  • The number of alpha and beta emitted in the nuclear reaction ""_(92)^(238)U to ""_(82)^(214)Pb is

    A
    `8 beta`
    B
    `6 alpha`
    C
    `2 beta`
    D
    `5 alpha`

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    The total nubmer of alpha "and" beta particles emitted in the nuclear reaction ._(92)^(238) U to _(82)^(214) Pb is :

    Calculate the number alpha-andbeta- particles emitted in the following reaction ""_(90)^(230)Thto""_(82)^(206)Pb

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