The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`.
The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`.
Text Solution
Verified by Experts
We know,
Conductivity = Conductance x Cell constant
`"k = G x Cell constant"`
`1.29xx=(1)/(100)xx"Cell constant"`
Cell constant `=1.29xx100m^(-1)=1.29cm^(-1)`
For `0.02` M KCl, R=520 ohm
Conductivity = Conductance x Cell constant
`k=(1)/(R)xx"Cell constant"`
`=(1)/(520)xx1.29=2.48xx10^(-3)"ohm"^(-1)cm^(-1)`
We know, `Lambda_(m)=kxx(1000)/(M)`
`=2.48xx10^(-3)xx(1000)/(0.02)=124"cm"^(2) "mol"^(-1)`
Conductivity = Conductance x Cell constant
`"k = G x Cell constant"`
`1.29xx=(1)/(100)xx"Cell constant"`
Cell constant `=1.29xx100m^(-1)=1.29cm^(-1)`
For `0.02` M KCl, R=520 ohm
Conductivity = Conductance x Cell constant
`k=(1)/(R)xx"Cell constant"`
`=(1)/(520)xx1.29=2.48xx10^(-3)"ohm"^(-1)cm^(-1)`
We know, `Lambda_(m)=kxx(1000)/(M)`
`=2.48xx10^(-3)xx(1000)/(0.02)=124"cm"^(2) "mol"^(-1)`
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Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given : Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ]
Resistance of a conductivity cell filled with 0.1 mol L^(-1) KCl solution is 100Omega . If the resistance of the same cell when filled with 0.02 mol L^(-1) KCl solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29S/m.
Knowledge Check
Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What is the conductivity of 0.02 M KCl solution ?
Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What is the conductivity of 0.02 M KCl solution ?
A
0.452 S `m^(-1)`
B
0.215 S `m^(-1)`
C
0.614 S `m^(-1)`
D
0.433 S `m^(-1)`
Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. SI unit for conductivity of a solution is
Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. SI unit for conductivity of a solution is
A
S `m^(-1)`
B
`Sm^(2)mol^(-1)`
C
`mol" "cm^(-3)`
D
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Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What will happen to the conductivity of the cell with the dilution ?
Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What will happen to the conductivity of the cell with the dilution ?
A
First decreases then increases
B
Increases
C
First increases then decreases
D
Decreases
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