The elctrical resistance of a column of `0.05 M N aOH ` solution of diameter `1 cm` and length `50 cm` is `5.55 xx 10^(3)ohm`. Calculate its resisteivity , conductivity, and molar conductivity.
Text Solution
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Area of cross-section `=pir^(2)=3.14xx(0.5)^(2)cm^(2)=0.785cm^(2)` We know, `R=rhoxx(1)/(A),5.55xx10^(3)=rhoxx(50)/(0.785)` `"Resistivity",rho=87.135"ohm cm"` `"Conductivity k"=(1)/(rho)=(1)/(87.135)-0.01148"S cm"^(-1)` Molar conductivity `Lambda_(m)` can be calculated as, `Lambda_(m)=kxx(1000)/(M)=0.01148xx(1000)/(0.05)` `=229.6"S cm"^(2)"mol"^(-1)`
The electrical resistance of a column of 0.05 M N aOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^(3)ohm . Calculate its resistivity , conductivity, and molar conductivity.
Calculating resistivity, conductivity and motor conductivity : The electrical resistance of a column of 0.05 mol L^(-1) NaOH solution of diameter 1 cm and length 50 cm is 55 xx 10^(3) ohm . Calculate its resistivity, conductivity and molar conductivity Strategy: Assuming the column of solution to be cylindrical determine the area of cross-section, A . Using it along with the length of column, calculate resistivity. Reciprocal of resistivity yields conductivity. When we divide conductivity by molar concentration, we get molar conductivity.
The electrical resistance of a column of 0.05 " mol " L^(-1) NaOH solution of diameter 1 cm and length 50 cm is 5.55xx10^(3)" ohm " .Calculate its resistivity,conductivity and molar conductivity.
The electrical resistance of a column of 0.04M NaOH solution of diameter 1.2 cm and length 50cm is 5.55xx10^(3)ohm , the resistivity of the column would be
The questions consist of two atatements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses : The electrical resistance of a column of 0.5 M NaOH solution of diameter 1 cm and length 50 cm is 5.55 xx 10^3 "ohm" . Its resistivity is equal to 75.234 Omega cm .
