The conductivity of `0.1`m KCl solution is `1.29sm^(-1)`. If the resistance of the cell filled with `0.1` M KCl is 100 ohm. Calculate the cell constant.
The specific conductivity of 0.1 N KCl solution is 0.0129 Omega^(-1) cm^(-1) . The resistane of the solution in the cell is 100 Omega . The cell constant of the cell will be
Resistance of a conductivity cell filled with 0.1 M KCl is 100 ohm. If the resistence of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. Conductivity of 0.1 KCl solution is 1.29xx10^(-2)" ohm "^(-1)cm^(-1) .
Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity
(a) Define the following terms : (i) Limiting molar conductivity, (ii) Fuel cell (b) Resistance of a conductivity cell filled with 0.1 molL^(-1)KCl solution is 100 Ohm. If the resistance of the same cell when filled with 0.2 mol L^(-1)KCl solution is 520 Ohm , calculate the conductivity and molar conductivity of 0.2 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29xx10^(-1) Scm^(-1) .
