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The conductivity of 0.1m KCl solution is...

The conductivity of `0.1`m KCl solution is `1.29sm^(-1)`. If the resistance of the cell filled with `0.1` M KCl is 100 ohm. Calculate the cell constant.

Text Solution

Verified by Experts

`k=GxxG^(**)rArrk=(1)/(R)xxG^(**)`
`G^(**)=kxxR=1.29xx100=129cm^(-1)`
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Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given : Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ]

Resistance of a conductivity cell filled with 0.1 M KCl is 100 ohm. If the resistence of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. Conductivity of 0.1 KCl solution is 1.29xx10^(-2)" ohm "^(-1)cm^(-1) .

Knowledge Check

  • The specific conductivity of 0.1 N KCl solution is 0.0129 Omega^(-1) cm^(-1) . The resistane of the solution in the cell is 100 Omega . The cell constant of the cell will be

    A
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    B
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  • Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 ohm. The conductivity of this solution is 1.29 Sm^(-1). Resistance of the same cell when filled with 0.2 M of the same solution is 520 ohm. The molar conductivity of 0.02 M solution of the electrolyte will be:

    A
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  • Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is (100Omega) . The conductivity of this solution is 1.29sm^(-1) . Resistance of the same cell when filled with 0.2 M of the same solution is 520Omega . The molar conductivity of (0.02)M solution of the electrolyte will be :

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    B
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    C
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    D
    ` 12.4xx10^(-4) sm ^(2) mol^(-1)`
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