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Two platinum electrodes were immersed i...

Two platinum electrodes were immersed in a solution of `CuSO_(4)` and electric current was passed through the solution. After some time, it was found that colour of `CuSO_(4)` disappeared with evolution of gas at the electrode. The colourless solution contains.

A

Platinum sulphate

B

Copper sulphate

C

Copper hydroxide

D

Sulphuric acid

Text Solution

Verified by Experts

The correct Answer is:
D
`2Cu^(+2)overset(+4e^(-))rarr2Cu` (cathode)
`2H_(2)O overset(-4e^(-))rarrO_(2)uparrow+4H^(+)("anode")2H^(+)+SO_(4)^(-2) rarrH_(2)SO_(4)`
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Electric current is passed through two cells 'A' and 'B' in series. Cell 'A' contains an aqueous solution of Ag_(2)SO_(4) and platinum electrodes. The cell 'B' contains aqueous solution of CuSO_(4) and Cu electrodes. The current is passed till 1.6 g of oxygen is liberated at the anode of cell 'A'. (i) Give equations for the reaction taking place at each electrode. (ii) Calculate the quantities of substances deposited at the cathodes of the two cells. (Ag= 108, Cu = 63.5)

Knowledge Check

  • t passed through the solution. After sometimes it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode. The colourless solution contains

    A
    platinum sulphate
    B
    copper hydroxide
    C
    copper sulphate
    D
    sulphuric acid.

  • The platinum electrodes were immersed in a solution of cupric sulphate and electric current was passed through the solution after sometime it was found that colour of copper sulphate disappeared with evolution of gas at the elctrode the colourless solution contains

    A
    Copper sulphate
    B
    copper hydroxide
    C
    platinum sulphate
    D
    sulphuric acid

  • Two platinum electrodes were immersed in a solution of CuSO_(4) and electric current was passed through the solution. After some time, it was fournd that the colour of CuSO_(4) disappeared with the evolution of O_(2)(g) at the electrode. Which statement is true regarding the resultant solution having pH=X?

    A
    `[Cu^(2+)]gt[SO_(4)^(2-)]`
    B
    `[Cu^(o+)]gt[Cu^(2+)]`
    C
    `[overset(c-)(O)H]gt[H^(o+)]`
    D
    `7gtX`

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    The colour of the light absorbed by an aqueous solution of CuSO_(4) is

    Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolytic cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly propertional to the amount of charge passed through it. The mass of substance liberated at electrode is calculated using the following relation : m= ("ItE")/(96500) Here, E represents the equivalent mass and 96500 C is called the Faraday constant. Faraday (96500 C) is the charge of 1 mole electron, i.e., 6.023 xx 10^(23) electrons, it is used to liberate one gram equivalent of the substance. The platinum electrodes were immersed in a solution of cupric sulphate (CuSO_(4)) and electric current is passed through the solution. after sometime, it was observed that the colour of copper sulphate disappeared with evolution of a gas at the electrode. The colourless solution contains :

    Two platinum electrodes were immersed in a solution of cupric sulphate and electric current sulphate and electric current passed through the solution. After sometime it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode . The colourless solution contains

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    The colour of light absorbed by an aqueous solution of CuSO_(4) is

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