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The time of oscillation of a small drop ...

The time of oscillation of a small drop of liquid under surface tension depends upon the density `rho`, radius r and surface tension S as :
`T prop rho^(a) S^(b) r^(c)`
find out a, b and c.

Text Solution

Verified by Experts

The correct Answer is:
`a=(1//2), b=(-1//2)` and `c=(3//2)`
`[T]=[M^(1)L^(-3)]^(a)[MT^(-2)]^(b)[L]^(c)`
Equate the exponents of similar quantities.
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Knowledge Check

  • Internal pressure inside a liquid drop of radius r and surface tension T is

    A
    `(2T)/r-P_(0)`
    B
    `(4T)/r + P_(0)`
    C
    `P_(0)+(2T)/r`
    D
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    A
    `(3)/(4)`
    B
    `sqrt3`
    C
    `(3)/(2)`
    D
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  • A spherical liquid drop is placed on a horizontal plane . A small distrubance cause the volume of the drop to oscillate . The time period oscillation (T) of the liquid drop depends on radius (r) of the drop , density (rho) and surface tension tension (S) of the liquid. Which amount the following will be be a possible expression for T (where k is a dimensionless constant)?

    A
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    B
    `ksqrt((rho^(2)r)/(S))`
    C
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    D
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