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Five vectors vecA, vecB, vecC,vecD and v...

Five vectors `vecA, vecB, vecC,vecD` and `vecE` have magnitude `10, 12 sqrt(2), 20, 20` and 10 unit respectively, they are direacted as shown in the fig. 3.58

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Text Solution

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The correct Answer is:
A
`vecA = 10hati," "vecB= 12 hati +12 hatj`
`vecC = - sqrt(3) 10hati + 10 hatj" ", " " vecp= 10hati-10sqrt(3) hatj`
`vecD = -10hatj`
`(vecA + vecB +vecC ) = (22-10sqrt(3)) hati + 22hatj`
x component = `22-10sqrt(3)`
y component = `22`
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Knowledge Check

  • Given : vecC=vecA+vecB . Also , the magnitude of vecA,vecB and vecC are 12,5 and 13 units respectively . The angle between vecA and vecB is

    A
    `0^@`
    B
    `pi/4`
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    A
    `cos^(-1) ((3)/(5))`
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    C
    `(pi)/(2)`
    D
    `sin^(-1) ((3)/(4))`

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