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If c and R denote capacity and resistanc...

If c and R denote capacity and resistance the dimensions of CR are :

A

`[M^(0)L^(0)T^(-1)]`

B

`[M^(1)L^(0)T^(2)]`

C

`[M^(0)L^(0)T^(1)]`

D

Not expressable in terms of `[M], [L]` and `[T]`

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The correct Answer is:
To find the dimensions of the product of capacity (C) and resistance (R), we will follow these steps: ### Step 1: Determine the dimension of Capacity (C) Capacity (C) is defined as the charge (Q) per unit voltage (V). Mathematically, it can be expressed as: \[ C = \frac{Q}{V} \] The dimension of charge (Q) is given by the dimension of current (I) multiplied by time (T): \[ [Q] = [I][T] = [A][T] \] Voltage (V) can be expressed in terms of work (W) and charge (Q): \[ V = \frac{W}{Q} \] Where the dimension of work (W) is energy, which has the dimension: \[ [W] = [M][L^2][T^{-2}] \] Substituting the dimension of charge into the equation for voltage: \[ [V] = \frac{[M][L^2][T^{-2}]}{[A][T]} = \frac{[M][L^2][T^{-2}]}{[A][T]} = [M][L^2][T^{-3}][A^{-1}] \] Now substituting the dimensions of Q and V back into the equation for C: \[ [C] = \frac{[A][T]}{[M][L^2][T^{-3}][A^{-1}]} = \frac{[A^2][T^4]}{[M][L^2]} \] Thus, the dimension of capacity is: \[ [C] = [M^{-1}][L^{-2}][T^4][A^2] \] ### Step 2: Determine the dimension of Resistance (R) Resistance (R) is defined as the ratio of voltage (V) to current (I): \[ R = \frac{V}{I} \] Substituting the dimension of voltage: \[ [R] = \frac{[M][L^2][T^{-3}][A^{-1}]}{[A]} = [M][L^2][T^{-3}][A^{-2}] \] ### Step 3: Calculate the dimensions of the product CR Now we can find the dimensions of the product \( CR \): \[ [CR] = [C] \times [R] \] Substituting the dimensions we found: \[ [CR] = \left([M^{-1}][L^{-2}][T^4][A^2]\right) \times \left([M][L^2][T^{-3}][A^{-2}]\right) \] ### Step 4: Simplify the dimensions Now, we will simplify the expression: \[ [CR] = [M^{-1}][M][L^{-2}][L^2][T^4][T^{-3}][A^2][A^{-2}] \] Combining like terms: - For mass (M): \( M^{-1} \times M = M^{0} \) - For length (L): \( L^{-2} \times L^2 = L^{0} \) - For time (T): \( T^4 \times T^{-3} = T^{1} \) - For current (A): \( A^2 \times A^{-2} = A^{0} \) Thus, we have: \[ [CR] = [M^0][L^0][T^1][A^0] = [T] \] ### Final Answer The dimensions of the product of capacity and resistance (CR) are: \[ [CR] = [T] \]

To find the dimensions of the product of capacity (C) and resistance (R), we will follow these steps: ### Step 1: Determine the dimension of Capacity (C) Capacity (C) is defined as the charge (Q) per unit voltage (V). Mathematically, it can be expressed as: \[ C = \frac{Q}{V} \] The dimension of charge (Q) is given by the dimension of current (I) multiplied by time (T): \[ [Q] = [I][T] = [A][T] \] ...
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Knowledge Check

  • If C and L denote to capacity and inductance, the dimensions of LC are :

    A
    `[M^(0)L^(0)T^(2)]`
    B
    `[M^(0)L^(2)T^(-2)]`
    C
    `[MLT^(-2)]`
    D
    `[M^(0)L^(0)T^(0)]`
  • If C and R denote capacitance and resistance dimensional formula of CR is:

    A
    `[M^0 L^0 T^1]`
    B
    `[M^0 L^0 T^0]`
    C
    `[M^0 L^0 T^(-1)]`
    D
    Not expressible in terms of MLT
  • IF C and denote capacitance and resistance, then find the dimesion of CR

    A
    `("ampere"^(2)-sec)/(Kg-"metre"^(2)//sec^(2))`
    B
    `("ampere-sec"^(2))/("Kg-metre/sec")`
    C
    `("ampere"^(2)-"sec"^(2))/("Kg-metre"^(2)//"sec"^(2))`
    D
    `("ampere"^(2)-"sec"^(2))/("Kg-metre"^(2)"sec"^(2))`
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