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Two masses m(1) and m(2) (m(1) lt m(2)) ...

Two masses `m_(1)` and `m_(2) (m_(1) lt m_(2))` are released from rest from a finite distance. They start under their mutual gravitational attraction

A

acceleration of `m_(1)` is more than that of `m_(2)`

B

acceleration of `m_(2)` is more than that of `m_(1)`

C

centre of mass of system will remain at rest in all the references frame

D

total energy of system remains constant

Text Solution

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The correct Answer is:
A, D
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Knowledge Check

  • Two masses m_(1) and m_(2)(m_(1)ltm_(2)) are released from rest finite distance. They start under their mutual gravitational attraction-

    A
    acceleration of `m_(1)` is more than that of `m_(2)`
    B
    acceleration of `m_(2)` is more than that of `m_(1)`
    C
    centre of mass of system will remain at rest in all the references frame.
    D
    total energy of system remains constant

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    A
    `sqrt((2K)/(d)[(1)/(m_(1))+(1)/(m_(2))])`
    B
    `sqrt((2K)/(d)[(1)/(m_(1))-(1)/(m_(2))])`
    C
    `sqrt((2K)/(d)[(m_(1)m_(2))/(m_(1)+m_(2))])`
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  • A smooth massless string passes over a smooth fixed pulley. Two masses m1 and m_(2) (m_(1) gt m_(2)) are tied at the two ends of the string. The masses are allowed to move under gravity starting from rest. The total external force acting on the two masses is

    A
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    B
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    C
    `(m_(1)-m_(2))g`
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    `((m_(1)+m_(2))^(2))/(m_(1)-m_(2))g`

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