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A particle moves in a circle of radius 1...

A particle moves in a circle of radius 10 m. Its linear speed is given by `v=3t` where t is the lime in second and v is in `ms^(-1)`.Compute the centripetal and tangential acceleration at time t = 2s.

Text Solution

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The linear speed at t = 2 s
`v=3t=6ms^(-1)`
The centripetal acceleration at t = 2 s is
`ac=(v^(2))/(r)=((6)^(2))/(10)=3.6ms^(-2)`
The tangential acceleration at `=(dv)/(dt)=3ms^(-2)`
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Knowledge Check

  • The velocity of a particle v at an instant t is given by v = a t + b t^(2) . Th e dimensions of b is

    A
    [L]
    B
    `[LT^(-1)]`
    C
    `[LT^(-2)]`
    D
    `[LT^(-3)]`

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