Home
Class 12
PHYSICS
Show that 1 amu = 932 MeV....

Show that 1 amu = `932 MeV`.

Text Solution

Verified by Experts

From Einstein's relation `E=mc^(2)`
`m=1 amu=1.661xx10^(-27)kg and c=2.998 10^(8)ms^(-1)`
`E=1.661xx10^(-27)xx(2.998xx10^(8))^(2)=14.929xx10^(-11)J`
`=(14.929xx10^(-11))/(1.602xx10^(-19))ev=9.318xx10^(8) MeV=931.8 MeV`
`therefore` Energy equivalent of `1 amu=932 MeV`.
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    SUBHASH PUBLICATION|Exercise FIVE MARKS QUESTIONS WITH ANSWERS|10 Videos
  • NUCLEI

    SUBHASH PUBLICATION|Exercise NUMARICALS WITH SOLUTIONS|26 Videos
  • NUCLEI

    SUBHASH PUBLICATION|Exercise TWO MARKS QUESTIONS WITH ANSWERS|14 Videos
  • MOVING CHARGES AND MAGNETISM

    SUBHASH PUBLICATION|Exercise NUMERICALS WITH SOLUTIONS|23 Videos
  • PUE BOARD MODEL QUESTION PAPER 1

    SUBHASH PUBLICATION|Exercise QUESTION|41 Videos

Similar Questions

Explore conceptually related problems

What is amu?

The atomic masses of Li, He and proton are 7.01823 amu, 4.00387 amu and 1.00715 amu respectively. Calculate the energy evolved in the reaction, 3^(Li^(7)) + 1^(HA^(1)) rarr 2 2^(He^(4)) + triangle E Given 1 amu = 931 MeV.

If the mass defect of ""_(4)^(9)X is a.m.u., then binding energy per nucleon is (1 a.m.u. = 931.5 MeV):

Show that (1- tan ^(2) A ) /( cot ^(2) A-1) =tan ^(2) A

Show that (x-1) is a factor of x ^(n)-1.

Show that (1, 0), (0, 1), (-3,4) are on a straight line.

Show that the matrix A=[(0, 1,-1),(-1,0,1),(1,-1,0)] is a skew symmetric matrix.

Show that the matrix A=[(1, -1, 5),(-1,2,1),(5,1,3)] is a symmetric matrix.