The linear mass density of a ladder of length `l` increases uniformly from one end `A` to the other end `B`,
(a) Form an expression for linear mass density as function of distance `x` from end `A` where linear mass density `lambda_(0)`. The density at one end being twice that of the other end.
(b) find the position of the centre of mass from end `A`.

Answer

`lamda(x)=lamda+(lamdax)/L`