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The linear mass density of a ladder of l...

The linear mass density of a ladder of length `l` increases uniformly from one end `A` to the other end `B`,
(a) Form an expression for linear mass density as function of distance `x` from end `A` where linear mass density `lambda_(0)`. The density at one end being twice that of the other end.
(b) find the position of the centre of mass from end `A`.

Text Solution

Verified by Experts

The correct Answer is:
`lamda(x)=lamda+(lamdax)/L`
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Knowledge Check

  • The linear mass density 'mu' of the string is (where, mass of the string = m, length of the string = L)

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    `mL^2`
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    A
    `(3l)/4((3a+b)/(2a+b))`
    B
    `(3l)/4((2a+b)/(3a+b))`
    C
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