A copper calorimeter of mass 100 gm contains 200 gm of a mixture of ice and water. Steam at 100°C under normal pressure is passed into the calorimeter and the temperature of the mixture is allowed to rise to 50°C. If the mass of the calorimeter and its contents is now 330 gm, what was the ratio of ice and water in beginning? Neglect heat losses.
Given : Specific heat capacity of copper
`=0.42xx10^3 J kg^(-1) K^(-1)`.
Specific heat capacity of water
`=4.2 xx10^3 J kg^(-1) K^(-1)`
Specific heat of fusion of ice
`=3.36xx10^5 J kg^(-1)`
Latent heat of condensation of steam
`=22.5 xx 10^5 J kg^(-1)`