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The elastic energy per unit volume is te...

The elastic energy per unit volume is terms of longitudinal strain `sigma` and Young's modulus `Y` is

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A metallic wire is suspended by suspending weight to it. If S is longitudinal strain and Y its young's modulus of elasticity then potential energy per unit volume will be

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Knowledge Check

  • Strain energy per unit volume is given by

    A
    `(1)/(2)xx(("stress")^(2))/(y)`
    B
    `(1)/(2)xx("stress")^(2)y`
    C
    `(1)/(2)xx("strain")/("stress")`
    D
    `(1)/(2)F l`

  • The elastic energy stored per units volume in a streched wire is

    A
    `(1)/(2)(("Stress"))/(Y)`
    B
    `(1)/(2)(("Stress")^(2))/(Y)`
    C
    `(1)/(2)(("Stress")^(2))/(Y^(2))`
    D
    `(1)/(2)(("Stress"))/(Y^(2))`

  • The unit of Young’s modulus is

    A
    `Nm^(2)`
    B
    `Nm^(-2)`
    C
    `Nm`
    D
    `Nm^(-1)`

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    A metallic wire of length L, area of cross-section A is suspended by attaching some wieght to it. If alpha is the longitudinal strain and Y is Young's modulus, find the ratio between elastic potential energy and the elastic energy density.

    The strain energy per unit volume of a stretched wire is

    Assertion If length of a wire is halved, its Young's modulus of elasticity will become two times. Reason The ratio of longitudinal stress and longitudinal strain is called Young's modulus of elasticity.

    The energy stored per unit volume of a strained wire is

    A metallic wire is suspended by attaching some weight to it. If alpha is the longitudinal strain and Y is Young's modulus, then the ratio of elastic potential energy to the energy density is equal to

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