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root(4)(81x^(8)y^(4)z^(16))...

root(4)(81x^(8)y^(4)z^(16))

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Assuming that x, y, z are positive real numbers, simplify each of the following . (i) sqrt(x^(3)y^(-2)) (ii) (x^(-2//3) y^(-1//2))^(2) (iii) ((x^(-4))/(y^(-10)))^((5)/(4)) (iv) (root4(81 x^(8)y^(8)z^(16))) div (root3(27x^(3)y^(6)z^(9))) (v) root5(x^(4) root4(x^(3)root3(x^(2)sqrt(x)))) (vi) ((sqrt(x))^(-(2)/(3)) sqrt(y^(4))) div (sqrt(xy^(-(1)/(2))) sqrt(x^(-2)y^(3)))

Find the square root of the following rational expressions. (400x^(4)y^(12)z^(16))/(100x^(8)y^(4)z^(4))

The square root of (256x^(8)y^(4)z^(10))/(25x^(6)y^(6)z^(6)) is equal to

(x-y)(x+y)(x^(2)+y^(2))(x^(4)+y^(4)) is equal ot: x^(16)-y^(16)(b)x^(8)-y^(8)x^(8)+y^(8)(d)x^(16)+y^(16)

Factorize: x^(4)-y^(4) (ii) 16x^(4)-81x^(4)-(y+z)^(4)( iv )2x-32x^(5)3a^(4)-48b^(4)(vi)81x^(4)-121x^(2)

If x=-2 and y=1, by using an identity find the value: (4y^(2)-9x^(2))(16y^(4)+36x^(2)y^(2)+81x^(4))

The value of ((256x^(16))/(81y^(4)))^(-(1)/(4))' is

Factorise: (i) 3x^(7)y -81x^(4)y^(4) (ii) a^(3) + 0.064