what are the frequency and wavelength of a photon emitted during a transition from n = 5 state to the n =2 state in the hydrogen atom?

Explanation

To find the frequency and wavelength of a photon emitted during a transition from \( n = 5 \) state to \( n = 2 \) state in the hydrogen atom, we can follow these steps:

### Step 1: Calculate the Energy Difference (\( \Delta E \))
The energy of an electron in a hydrogen atom is given by:
\[ E_n = -2.18 \times 10^{-18} \, \text{J} \times \frac{1}{n^2} \]

For the transition from \( n = 5 \) to \( n = 2 \):
\[ \Delta E = E_2 - E_5 \]
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