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Statement - 1 : If a concentric spheeric...

Statement - 1 : If a concentric spheerical Gaussian surface is drawn inside thin spheical shell charge, electric field (E) at each point of surface must be zero.
Statement - 2 : In accordance with Gauss's law
`phi_(E)=oint vec(E).d vec(A)=(Q_("net enclosed"))/(epsilon_(0))`
`Q_("net enclosed")=0" implies "phi_(E)=0`

A

Statement - 1 is true, Statement - 2 is true and statement -2 is correct explanation for statement - 1.

B

Statement - 1 is true, Statement - 2 is ture and statement - 2 is NOT correct explanation for statement - 1.

C

Statement - 1 is true, statement - 2 is false.

D

Statement - 1 is false, statement - 2 is true.

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Statement-1: Suppose that a Gaussian surface enclose no net charge. Gauss law requires that electric field equals zero for all points on the surface. Statement-2: If electric field equals zero everywhere on the surface, Gauss law requires that there be no net charge inside.

    A
    Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.
    B
    Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.
    C
    Statement-1 is true, statement-2 is false.
    D
    Statement -1 is false, statement -2 is true.
  • If net charge enclosed by a Gaussian surface is zero, then Assertion :- vecE at any point on Gaussian surface is 0. Reason :- No net charge is enclosed by Gaussian surface, so E = 0

    A
    If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
    B
    If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
    C
    If Assertion is True but the Reason is False.
    D
    If both Assertion & Reason are False.
  • Assertion(A):If Gaussian surface does not enclose any charge then vec(E) at any point on the Gaussian surface must be zero. Assertion(R ):No net charge is enclosed by Gaussians surface,so net flux passing through the surface is zero.

    A
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    B
    Both `A` and `R` are True but `R` is not the correct explanation of `A`.
    C
    `A` is true and `R` is false
    D
    `A` is false and `R` is true.
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