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In a photo-emissive cell, with exciting ...

In a photo-emissive cell, with exciting wavelength `lambda`, the maximum kinetic energy of electron is K. If the exciting wavelength is changed to `( 3 lambda)/( 4)` the kinetic energy of the fastest emitted electron will be `:`

A

`3K //4`

B

`4K //3`

C

less than `4K//3`

D

greater than `4K//3`

Text Solution

Verified by Experts

The correct Answer is:
D
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