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A smooth wire is bent into a vertical ci...

A smooth wire is bent into a vertical circle of radius a. `A` bead `P` can slide smoothly on the wire. The circle is rotated about vertical diameter AB as axis with a speed omega as shown in figure. The bead `P` is ar rest w.r.t. the circular ring in the position shown. then `omega^(2)` is equal to:

A

2g/a

B

2g / (a `sqrt(3)`)

C

g `sqrt(3) `g /a

D

2a / (g `sqrt(3)`)

Text Solution

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The correct Answer is:
B
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Knowledge Check

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