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Find the angles of the parallelogram ABC...

Find the angles of the parallelogram ABCD , if `angleC : angleD = 4 : 5 `

Text Solution

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The correct Answer is:
`80^(@),100^(@),80^(@),100^(@)`
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Knowledge Check

  • The other angles of the parallelogram ABCD, if one of its angles is 60^(@) , are

    A
    `100^(@), 60^(@),140^(@)`
    B
    `120^(@), 60^(@),120^(@)`
    C
    `80^(@), 60^(@),160^(@)`
    D
    `110^(@), 60^(@),130^(@)`

  • If angleA : angleB=3:1 in the parallelogram ABCD , then angleA =

    A
    `45^(@)`
    B
    `90^(@)`
    C
    `135^(@)`
    D
    `145^(@)`

  • In the parallelogram ABCD , angleBAD= 100^(@)and angleCBD=45^(@), " then" angleBDC=

    A
    `35^(@)`
    B
    `45^(@)`
    C
    `60^(@)`
    D
    `75^(@)`

    • Similar Questions

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    In the parallelogram ABCD , angleB-angleC=60^(@). "Find"angleA and angleD

    The bisectors of angleA and angleB of the parallelogram ABCD meet at the point P on the side CD. If the length of the side AB be 4 cm , find the length BC.

    E is any point on the side BC of the parallelogram ABCD. If DeltaABEandDeltaDCE have the areas 10 sq.cms and 12 sq.cms respectively, then the area of the parallelogram ABCD =

    Two vertices of the parallelogram ABCD are A( 8 , 14 , 12) and B( 4 , 6 , 4) and its diagonals intersect at ( 3 , 5 , 5) , find the coorinates of vertices C and D .

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