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P is a variable point and the co-ordinates of two points A and B are (–2, 2, 3) and (13, –3, 13) respectively. Find the locus of P if 3PA = 2PB.

Answer

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If the coordinates of two points A and B are (3,\ 4) and (5,\ -2) respectively. Find the coordinates of any point P , if PA = PB, and area of triangle PAB is 10.

The line segment joining the points (3, -4) and (1, 2) is trisected at the points P and Q. If the co-ordinates of P and Q are (p,-2) and ((5)/(3), q) respectively, find the values of p and q.

Knowledge Check

  • Coordinates of the points A, B, C,D are (13,7), (-5,2), (7,3) and (3,7) respectively. Let AB and CD meet at P, then PA:PB is equal to

    A
    `6:7`
    B
    `6:7`
    C
    `7:6`
    D
    None of these
  • The coordinates of the point Q symmetric to the point P(–5, 13) with respect to the line 2x – 3y – 3 = 0 are -

    A
    (11, –11)
    B
    (5, –13)
    C
    (7, –9)
    D
    (6, –3)
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