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The value of DeltaH("sol") of BaCl(2) (s...

The value of `DeltaH_("sol")` of `BaCl_(2) (s)` and `BaCl_(2) . 2 H_(2)O` (s) are - a kJ and b kJ respectively . The value of `DeltaH_("Hydration")` of `BaCl_(2) (s)` is -

A

` b - a`

B

`a + b `

C

`-a-b`

D

`a - b`

Text Solution

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The correct Answer is:
C
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Enthalpies of solution of BaCl_(2)(s) and BaCl_(2).2H_(2)O(s) are -20 kJ//"mole" and 8.0kJ//"mole" respectively. Calculate heat of hydration of BaCl_(2)(s) .

Enthalpy of solution ( Delta H ) for BaCl_(2). 2H_(2) O and BaCl_(2) are 8.8 and -20.6 kJ mol^(-1) respectively. Calculate the heat of hydration of BaCl_(2) to BaCl_(2). 2H_(2)O .

Knowledge Check

  • the enthalpy of dissolution of BaCl _(2) (s) and BaCl_(2). 2H_(2)O(s) are - 20 . 6 and 8.8 kJ // mol respectively. The enthalpy of hydration for BaCl_(2)(s) + 2H_(2)O to BaCl_(2) . 2H_(2)O(s) is

    A
    29. 4 kJ
    B
    `-29 . 4 kJ`
    C
    `-11.8 kJ`
    D
    38.2 kJ

  • The enthalpy of solution of BaCl_(2)(s) and BaCl_(2).2H_(2)O(s) are -20.6 and 8.8 kJ mol^(-1) respectively. The enthalpy change for the reaction BaCl_(2)(s)+2H_(2)OrarrBaCl_(2).2H_(2)O is

    A
    29.4 kJ
    B
    `- 11.8 kJ`
    C
    `- 20.6 kJ`
    D
    `- 29.4 kJ`

  • The enthalpy of dissolution of BaCl_(2)(s) and BaCl_(2).2H_(2)O are -20.6 and 8.8 KJ mol^(-1) respectively . Calculate enthalpy of hydration forgiven reaction: BaCl_(2)(s)+2H_(2)OtoBaCl_(2).2H_(2)O(s)

    A
    `-29.4KJ`
    B
    `-35.4KJ`
    C
    `-24.4KJ`
    D
    `-15.2KJ`

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