Home
Class 12
MATHS
Consider the curve x=1-3t^(2),y=t-3t^(2)...

Consider the curve `x=1-3t^(2),y=t-3t^(2)`. If tangent at point `(1-3t^(2),t-3t^(2))` inclined at an angle `theta` to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q.
The value of `tan theta+ sec theta ` is equal to-

A

`3t`

B

`t`

C

`t-t^(2)`

D

`t^(2)-2t`

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Topper's Solved these Questions

  • TANGENT AND NORMAL

    CHHAYA PUBLICATION|Exercise ASSERTION-REASON TYPE|2 Videos

  • TANGENT AND NORMAL

    CHHAYA PUBLICATION|Exercise INTEGER ANSWER TYPE|5 Videos

  • STRAIGHT LINE IN THREE DIMENSINAL SPACE

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination|19 Videos

  • TRANSFORMATIONS OF SUMS AND PRODUCTS

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos

Similar Questions

Explore conceptually related problems

Consider the curve x=1-3t^(2),y=t-3t^(2) . If tangent at point (1-3t^(2),t-3t^(2)) inclined at an angle theta to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q. The point Q will be-

Consider the curve x=1-3t^(2),y=t-3t^(2) . If tangent at point (1-3t^(2),t-3t^(2)) inclined at an angle theta to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q. The angle between the tangent at P and Q will be-

The curve x=1-3t^(2), y=t-3t^(3) is symmetrical with respect to -

If sin theta = (2t)/(1+t^(2)) and theta lies in the second quadrant, then cos theta is equal to

If sin^3theta+sinthetacos^2theta=1,t h e ntheta is equal to (n in Z)

Find the equation of the tangent to the parabola y^2=4a x at the point (a t^2,\ 2a t) .

The slope of the tangent to the curve x= t^(2)+3t-8,y=2t^(2)-2t-5 at the point (2,-1) is

Find the equation of the tangents and normal to the curve x= sin 3t, y= cos 2t " at " t=(pi)/(4)

If the tangents to y^2=4ax at the point (at^2,2at) where |t|>1 is a normal x^2-y^2=a^2 at the point (asectheta,a tan theta) , then t=