Identify the compounds A, B and C in the following reaction and write their names:
`A(C_5H_(10))overset((i)O_3)underset((ii)Zn//H_2O)toB(C_3H_6O)+C(C_2H_4O)`

Explanation

Carbonyl compounds B and C contains three and two carbon atoms respectively. There are also three carbon atoms on one side of the double bond and two carbon atoms on the other side of the double bond in the alkene. Therefore two, alkenes with molecular formula `C_5H_(10)` are : 2-methylbut -2-ene `[CH_3-C(CH_3)=CHCH_3] ` and pent-2-ene `(CH_3CH_2CH=CHCH_3)` . If A `(C_5H_(10))` is 2-methylbut -2-ene, then B `(C_3H_6O) &C(C_2H_4O)` are acetone `(CH_3COCH_3)` & acetaldehyde `(CH_3CHO)` respectively.

If A is pent-2-ene then B and C are propanal `(CH_3CH_2CHO)` & acetaldehyde `(CH_3CHO)` respectively.
`underset("Pent-ene"(A))(CH_3CH_2CH=CHCH_3)overset((i)O_3)underset((ii)Zn//H_2O)tounderset("Propanal (B)Acetaldehyde"(C ))(CH_3CH_2CHO+CH_3CHO)`