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Suggest a way to determine the Lambda(m)...

Suggest a way to determine the `Lambda_(m)^(@)` value of water.

Text Solution

Verified by Experts

`Lambda_(m)^(@)` of water can be determined by using Kohlrausch law.
`Lambda_(m)^(@)(H_(2)O)=lambda_(H^(+))^(@)+lambda_(OH^(-))^(@)`. If `Lambda_(m)^(@)(HCl), Lambda_(m)^(@)(NaOH)` and `lambda_(m)^(@)(NaCl)` are known, `Lambda_(m)^(@)(H_(2)O)` can be calculated by using the relation,
`Lambda_(m)^(@)(H_(2)O)=Lambda_(m)^(@)(HCl)+Lambda_(m)^(@)(NaOH)-Lambda_(m)^(@)(NaCl)`
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Knowledge Check

  • Lambda_(m(H_(2)O)^(@) is equal to -

    A
    `Lambda_(m(HCl))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaCl))^(@)`
    B
    `Lambda_(m(HNO_(3)))^(@)+Lambda_(m(NaNO_(3)))^(@)-Lambda_(m(NaOH))^(@)`
    C
    `Lambda_(m(HNO_(3)))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaNO_(3)))^(@)`
    D
    `Lambda_((NH_(4)OH))^(@)+Lambda_(m(HCl))^(@)-Lambda_(m(NH_(4)Cl))^(@)`

  • At 26^(@)C, Lambda_(m)^(@)(NH_(4)Cl)="129.8 ohm"^(-1)."cm"^(2)."mol"^(-1) and Lambda_(m)^(@)(NaCl)="126.5 ohm"^(-1)."cm"^(2)."mol"^(-1) . Apart from the values of Lambda_(m)^(@)(NH_(4)Cl) and Lambda_(m)^(@)(NaCl) , which of the following quantities should be known, to determine the value of Lambda_(m)^(@)(NH_(4)OH)-

    A
    molar ionic conductance of `OH^(-)(aq)` at infinite dilution
    B
    `Lambda_(m)^(@)` value of NaOH solution
    C
    extent of ionisation of `NH_(4)OH`
    D
    `Lambda_(m)^(@)` value of HCl solution

  • Lambda_(m(NH_(4)OH)^(@) is equal to -

    A
    `Lambda_(m(NH_(4)OH))^(@)+Lambda_(m(NH_(4)Cl))^(@)-Lambda_(HCl)^(@)`
    B
    `Lambda_(m(NH_(4)Cl))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaCl))^(@)`
    C
    `Lambda_(m(NH_(4)Cl))^(@)+Lambda_(m(NaCl))^(@)-Lambda_(m(NaOH))^(@)`
    D
    `Lambda_(m(NaOH))^(@)+Lambda_(m(NaCl))^(@)-Lambda_(m(NH_(4)Cl))^(@)`

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    Write down Kohlrausch's law of independent migration of ions. Find out the molar conductivity of ammonium hydroxide at infinite dilution (Lambda_(m)^(@)) at 298K, given that (Lambda_(m)^(@)) values for NH_(4)Cl, NaCl and NaOH are 149, 126 and "248 S.cm"^(2)."mol"^(-1) respectively at 298 K.

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