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Benzene and toluene form a nearly ideal ...

Benzene and toluene form a nearly ideal solution. At a certain temperature, calculate the vapour pressure of solution containing equal moles of two substances `("Given ",p_("toluene")^0=55mm" "Hg,p_("benzene")^0=150mm" "Hg]`

Text Solution

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As the number of moles of toluene and benzene are equal, `x_("toluene"),x_("benzene")=0.5`
`:.` According to Raoult's law, the vapour pressure of the solution, `P=x_("toluene")*P_("toluene")^0+x_("benzene")*P_("benzene")^0`
`=(0.5xx55+0.5xx150)mm" "Hg`
`=(27.5+75)mm" "Hg=102.5mm" "Hg`
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  • At 40^@C , the vapour pressure of pure liquids, benzene and toluene, are 160 mm Hg and 60 mm Hg respectively. At the same temperature, the vapour pressure of an equimolar solution of the two liquids, assuming the ideal solution should be

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