Calculate the % ionic character for molecule AB when E.N. different is 2.0:

Options

A. `46%`
B. `36%`
C. `30%`
D. `50%`

Explanation

To calculate the percentage ionic character for the molecule AB when the electronegativity difference (ΔEN) is 2.0, we can follow these steps:

### Step 1: Identify the formula for percentage ionic character
The formula to calculate the percentage ionic character is given by:
\[ \text{Percentage Ionic Character} = 16 \times \Delta EN + 3.5 \times (\Delta EN)^2 \]

### Step 2: Substitute the given value of ΔEN
We know that ΔEN = 2.0. Now, we will substitute this value into the formula:
\[ \text{Percentage Ionic Character} = 16 \times 2.0 + 3.5 \times (2.0)^2 \]

### Step 3: Calculate each term
First, calculate the first term:
\[ 16 \times 2.0 = 32 \]

Next, calculate the second term:
\[ (2.0)^2 = 4 \]
Now substitute this back into the equation:
\[ 3.5 \times 4 = 14 \]

### Step 4: Add both terms together
Now, we will add the results from Step 3:
\[ 32 + 14 = 46 \]

### Step 5: State the final result
Thus, the percentage ionic character for the molecule AB when the electronegativity difference is 2.0 is:
\[ \text{Percentage Ionic Character} = 46\% \]

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