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An alcohol of unknown structure gave a p...

An alcohol of unknown structure gave a positive Lucas test in about five minutes. When alcohol was heated with concentrated `H_(2)SO_(4)` an alkene was formed with the formula `C_(4)H_(8)`. Ozonolysis of this alkene gave a single product, `C_(2)H_(4)O`. What was the structure of the alcohol ?

Text Solution

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The ozonolysis product of alkene `C_(4)H_(8)` is `C_(2)H_(4)O` i.e. ethanal `(CH_(3)CH=O)`. Since tow molecules of ethanal have been dormed therefore, alkene is but-2-ene `(CH_(3)CH=CH-CH_(3))`.

The alkene has beeen formed by the dehydraction of alcohol with concentratrated sulphuric acid. Since the alcohol gives a positive Lucas test within five minutes, it is expected to be a secondary alcohol. It is therefore, butan-2-ol `(CH_(3)CHOHCH_(2)CH_(3))`
`underset("Butan-2-ol")(CH_(3)-overset(OH)overset(|)(CH)-CH_(2)-CH_(3)) underset("Heat")overset(H_(2)SO_(4) (conc.))(rarr) underset("But-2-ene")(CH_(3)-CH=CH-CH_(3))`
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Knowledge Check

  • When alcohol reacts with concentrated H_(2)SO_(4) intermediate compound formed is

    A
    carbonium ion
    B
    alkoxy ion
    C
    alkyl hydrogen sulphate
    D
    none of these
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    A
    carbonium ion
    B
    alkoxy ion
    C
    alkyl hydrogen sulphate
    D
    none of these.
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    A
    Carbonium ion
    B
    Alkoxy ion
    C
    Alkyl hydrogen sulphate
    D
    None of these
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