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The concentration of R in the reaction R...

The concentration of `R` in the reaction `R rarr P` was measured as a function of time and the following data were obtained. What is the order of the reaction?
`|{:([R] (mol),1.0,0.75,0.40,0.10),(T (min),0.0,0.05,0.12,0.18):}|`

Text Solution

Verified by Experts

The correct Answer is:
`(A) rarr0`
Rate of reaction in the interval of 0.05 to 0.12 min
`=(1.0-0.75)/(0.05)= 5 "mol L"^(-1)"min"^(-1)`
Rate of reaction in the interval 0.05 to 0.12 min
`=(0.75-0.40)/(0.12-0.05)=5 "mol L"^(-1)"min"^(-1)`
Rate of reaction in the interval 0.12 ot 0.18 min
`=(0.40-0.10)/(0.18-0.12)=5 "mol L"^(-1)"min"^(-1)`
The rate of reaction remains constant irrespective the change of concentrations. Hence it is a reaction of zero order
Alternatively, for zero reaction, `k=(x)/(t)` and k comes out to be constant.
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Knowledge Check

  • The concentration of R in the reaction R rarr P was measured as a function of time and the following data was obtained {:("[R]",1,0.5,0.25,0.125),("Time",0,0.05,0.1,0.15):} The order of reaction is :

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    D
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    B
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    D
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