What will be the molarity of a solution, which contains 5.85g of `NaCl(s)` per 500mL?

Options

A. `4 "mol" L^(-1)`
B. `20 "mol"L^(-1)`
C. `0.2"mol"L^(-1)`
D. `2 "mol"L^(-1)`

Answer

C

Explanation

Since, molarity (M) is calculated by following equation
`"molarity"=("weight"xx1000)/("molecular weight"xx"volume"(mL))`
`=(5.85xx1000)/(58.5xx500)=0.0"mol"L^(-1)`