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The density of 3 molal solution of NaOH ...

The density of 3 molal solution of NaOH is 1.110g `mL^(-1)`. Calculate the molarity of the solution.

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To calculate the molarity of a 3 molal solution of NaOH with a density of 1.110 g/mL, follow these steps: ### Step 1: Understand the definition of molality Molality (m) is defined as the number of moles of solute per kilogram of solvent. A 3 molal solution means there are 3 moles of NaOH in 1 kg of solvent (water). ### Step 2: Calculate the weight of the solute (NaOH) To find the weight of the solute, we need to use the molar mass of NaOH. The molar mass of NaOH is calculated as follows: - Sodium (Na) = 23 g/mol ...
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The density of 3 molal solution of NaOH is "1.110 m mL"^(-1) . Calculate the molarity of the solution.

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Knowledge Check

  • The density of 1 M solution of NaCl is 1.0585 g mL^(-1) . The molality of the solution is

    A
    1.0585
    B
    `1.00`
    C
    `0.10`
    D
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  • The density of 3M solution of sodium chloride is 1.252 g mL^(-1) . The molality of the solution will be: (molar mass, NaCI= 58.5 g mol^(1) )

    A
    260 m
    B
    2.18 m
    C
    2.79 m
    D
    3.00 m

  • The density of of 3 M solution of sodium chloride is 1.252 g mL(-1) . The molality of the solution will be (molar mass, NaCl = 58.5 g mol(-1)L)

    A
    2.60 m
    B
    2.18 m
    C
    2.79 m
    D
    3.00 m

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