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An organic compound undergoes first deco...

An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`

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An organic compound undergoes first-order decomposition . The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t_(1//8) and t_(1//10) respectively . What is the value of ([t_(1//8)])/([t_(1//10)]) xx 10 (take log_(10) 2 = 0.3 )

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1//8 and 1//10 of its initial concentration are t_(1//8) and t_(1//10) respectively. What is the value of ([t_(1//8)])/([t_(1//10)])xx10?(log_(10)2=0.3)

Knowledge Check

  • An organic compound undergoes first order decomposition . The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t_(1//8) and t_(1//10) respectively. What is the value of ([t_(1//8)])/([t_(1//10)]) ? (take log_(10)2=0.3 )

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    D
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    A
    `0.6932 times 10^-2 min`
    B
    `0.6932 times 10^-3 `min
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