An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`
For a first order reaction, t_(7//8) = n xx t_(1//2) . The value of n will be .......... .
The rate for a first order reaction is 0.6932 xx 10^(-2) mol L^(-1) "min"^(-1) and the initial concentration of the reactants is 1M , T_(1//2) is equal to
