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1.22 g of benzoic acid is dissolved in (...

`1.22 g` of benzoic acid is dissolved in (i) 100g acetone `(K_(b)` for acetone `=1.7)` and (ii) 100 g benzene `(K_(b)` for benzene `= 2.6)`. The elevation in boiling points `T_(b)` is `0.17^(@)C` and `0.13^(@)C` respectively.
(a) What are the molecular weights of benzoic acid in both the solutions?
(b) What do you deduce out of it in terms of structure of benzoic acid?

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The correct Answer is:
A
It means that benzoic acid remains as it is in acetone while it dimerises in benzene as
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Knowledge Check

  • A solution of 0.640 g of azulene in 100.0 g of benzene is 80.23^(@)C . The boilingpoint of benzeneis 80.10^(@)C , and K_(b) is 2.53^(@)C /molal What is the moleculer mass of azulene?

    A
    108
    B
    99
    C
    125
    D
    134

  • To observe an elevation of boiling point of 0.05^(@)C , the amount of a solute (molecular weight = 100) to be added to 100 g of water (K_(b) = 0.5) is

    A
    2 g
    B
    0.05 g
    C
    1 g
    D
    0.75 g

  • 12.2gm benzoic acid (M =122) in 100g H_(2)O has elevation of boiling point of 0.27^(@)C, K_(b) = 0.54 K kg/mole. If there is 100% dimerization the no.of molecules of benzoic acid in associated sate is:

    A
    1
    B
    2
    C
    3
    D
    4
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