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1.22 g of benzoic acid is dissolved in (...

`1.22 g` of benzoic acid is dissolved in (i) 100g acetone `(K_(b)` for acetone `=1.7)` and (ii) 100 g benzene `(K_(b)` for benzene `= 2.6)`. The elevation in boiling points `T_(b)` is `0.17^(@)C` and `0.13^(@)C` respectively.
(a) What are the molecular weights of benzoic acid in both the solutions?
(b) What do you deduce out of it in terms of structure of benzoic acid?

Text Solution

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The correct Answer is:
A
It means that benzoic acid remains as it is in acetone while it dimerises in benzene as
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12.2 g of benzoic acid is dissolved in (i) 1 kg acetone (K_(b) = 1.9 K kg mol^(-1)) and (ii) 1 kg benzene (K_(b) = 2.6 K kg mol^(-1) . The elevation of boiling points are 0.19^(@)C and 0.13^(@) C , respectively. a. What are the molar masses of benzoic acid in the two solutions ? , b. What are the structures of benzoic acid in the two solutions ?

1.22 g of benzoic acid is dissolved in 100 g of acetone and 100 g of acetone seperately. Boiling point of the solution in acetone increases by 0.17^(@) C, while that of solution, in benzene increases by 0.13^(@) C , K_(b) for acetone and benzene is 1.7 K kg mol^(-1) and 2.6 K kg mol^(-1) . Find molecular weight of benzoic acid in two cases. Hence, find their sum.

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