Find the equation of the perpendicular bisector of AB, where A and B are the points (3,6) and (`-3,4)` respectively. Also, find its points of intersection with (i) x-axis (ii) y-axis.

Explanation

Let `P(x,y)` be any point on the perpendicular bisector of `AB`.
Then,
`PA=PB`

`=>sqrt((x−3)^2+(y−6)^2)
​=sqrt((x+3)^2+(y−4)^2
)​`

`=>(x−3)^2+(y−6)^2=(x+3)^2+(y−4)^2`

`=>x^2−6x+9+y^2−12y+36=x^2+6x+9+y^2−8y+16`

`=>12x+4y−20=0`

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