Prove that the diagonals of a rectangle bisect each other and are equal.

Explanation

Let `OABC` is a rectangle and `O(0,0),A(a,0),B(a,b)` and `C(0,6)`

Let diagonal `OB` and `AC` bisects each other at point `P`

Co-ordinate of midpoint `P`

`OB=((0+a)/2,(0+b)/2)
=(a/2​,b/2​) `


Co-ordinate of mid point of P

`AC=((a+0)/​2,(0+b)/2​) `
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