The relative reactivity of `1^(@), 2^(@)` and `3^(@)` hybrogen's towards chlorination is `1 : 3.8 : 5`. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.

Explanation

The given organic compound is `CH_(3)-overset(CH_(3))overset(|)underset(2-"methyl butane")(CH-CH_(2)-CH_(3)`
The compound has 9 primary hydrogen, 2 secondary and one tertiary hybrogen atoms . The relative reactivity of `1^(@), 2^(@)` and `3^(@)` hydrogen atoms towards chlorination is `1 : 3.8 : 5` . Relative amout of product after chlorination=Number of hydrogen `xx` relative reactivity
`{:("Relative",1^(@)"halide",2^(@)"halide",3^(@) "halide",),("amount",9xx1=9,2xx3.8=7.6,1xx5=5,):}`
Total amount of mono chloro product = `9+7.6 + 5 = 21.6`
Percentage of `1^(@)` mono chloro product = `9/21.6xx100=41.7%`
Percentage of `2^(@)` mono chloro product = `7.6/21.6xx100=352%`
percentage of `3^(@)` mono chloro product = `5/21.6xx100= 23.1%`