Reactions of `C_(6)H_(5)CH_(2)Br` with aqueous sodium hydroxide follows:

Options

A. `S_(N)1` mechanism
B. `S_(N)2` mechanism
C. Any of the above two depending upon the temperature of reaction
D. saytzeff rule

Explanation

To solve the question regarding the reaction of `C6H5CH2Br` (benzyl bromide) with aqueous sodium hydroxide, we will analyze the mechanism involved in this reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are benzyl bromide (`C6H5CH2Br`) and aqueous sodium hydroxide (`NaOH`).

2. **Understand the Nature of the Reaction**:
Benzyl bromide contains a bromine atom that acts as a leaving group. When it reacts with sodium hydroxide, we need to determine whether the reaction follows an SN1 or SN2 mechanism.

3. **Consider the Mechanism**:
- **SN1 Mechanism**: This mechanism involves the formation of a carbocation intermediate. The leaving group (Br) departs first, forming a carbocation, which is then attacked by the nucleophile (OH⁻).
- **SN2 Mechanism**: This mechanism involves a single concerted step where the nucleophile attacks the substrate as the leaving group departs.

4. **Analyze the Carbocation Stability**:
In the case of benzyl bromide, when the bromine leaves, it forms a benzyl carbocation (`C6H5CH2+`). This carbocation is resonance-stabilized due to the adjacent aromatic ring, making it relatively stable.

5. **Determine the Reaction Pathway**:
Given the stability of the benzyl carbocation, the reaction will favor the SN1 pathway. The bromine leaves first, forming the stable carbocation, and then the hydroxide ion (OH⁻) from the sodium hydroxide attacks the carbocation.

6. **Write the Reaction**:
The overall reaction can be summarized as follows:
\[ C6H5CH2Br + NaOH \rightarrow C6H5CH2OH + NaBr \]
Here, benzyl alcohol (`C6H5CH2OH`) is formed as the product.

### Final Answer:
The reaction of `C6H5CH2Br` with aqueous sodium hydroxide follows the **SN1 mechanism**, resulting in the formation of benzyl alcohol.

---