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The total number of local maxima and loc...

The total number of local maxima and local minima of the function f(x) = `{{:( (2 + x)^(3) "," , -3 lt x le -1) , (x^(2//3) "," , -1 lt x lt 2):}` is

A

0

B

1

C

2

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To find the total number of local maxima and local minima of the function given, we will analyze the function piecewise and find the critical points by differentiating the function. ### Step-by-Step Solution: 1. **Define the Function:** The function is defined piecewise as follows: \[ f(x) = \begin{cases} (2 + x)^3 & \text{for } -3 < x \leq -1 \\ x^{2/3} & \text{for } -1 < x < 2 \end{cases} \] 2. **Differentiate Each Piece:** We need to find the derivative \( f'(x) \) for each piece of the function. - For the first piece \( f(x) = (2 + x)^3 \): \[ f'(x) = 3(2 + x)^2 \cdot (1) = 3(2 + x)^2 \] - For the second piece \( f(x) = x^{2/3} \): \[ f'(x) = \frac{2}{3} x^{-1/3} = \frac{2}{3\sqrt[3]{x^2}} \] 3. **Find Critical Points:** Set the derivatives equal to zero to find critical points. - For \( f'(x) = 3(2 + x)^2 \): \[ 3(2 + x)^2 = 0 \implies (2 + x)^2 = 0 \implies x = -2 \] This critical point \( x = -2 \) is in the interval \( -3 < x \leq -1 \). - For \( f'(x) = \frac{2}{3\sqrt[3]{x^2}} \): The derivative does not equal zero for any \( x \) in the interval \( -1 < x < 2 \) since \( x^{2/3} \) is always positive in this interval. 4. **Check Endpoints:** We also need to check the endpoints of the intervals: - At \( x = -1 \): \[ f(-1) = (-1)^{2/3} = 1 \] - At \( x = 2 \): \[ f(2) = 2^{2/3} \text{ (which is positive)} \] 5. **Determine Local Maxima and Minima:** - The critical point \( x = -2 \) is the only critical point found in the first interval. - Since \( f'(x) > 0 \) for \( x > -2 \) in the first piece, it indicates that \( x = -2 \) is a local minimum. - In the second piece, there are no critical points, and since the function is increasing, there are no local maxima or minima. 6. **Count Local Maxima and Minima:** - From the analysis, we have: - 1 local minimum at \( x = -2 \) - 0 local maxima ### Conclusion: The total number of local maxima and local minima of the function is: \[ \text{Total = 1 (local minimum) + 0 (local maxima) = 1} \]
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Knowledge Check

  • The total number of local maxima and local minima of the function f(x) = {{:((2 + x)^3,-3 lt x le -1),(x^(2//3),-1 lt x lt x):} is

    A
    0
    B
    1
    C
    2
    D
    3
  • The points of local maxima or local minima of the function f(x) = x^(3) + x^(2) + x + 1 are:

    A
    0, 1, 1
    B
    `-1, 0,1`
    C
    `-1, -1, 0`
    D
    Does not exist
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