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For a particle displacement time relatio...

For a particle displacement time relation is `t = sqrt(x) + 3`. Its displacement when its velocity is zero -

A

0

B

-2

C

2

D

1

Text Solution

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The correct Answer is:
A
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The relation 3t=sqrt(3x)+6 describes the displacement of a particle in one" direction where "x" is in metres and t in sec.The displacement,when velocity is zero,is meters.

The displacement x of a particle varies as sqrt(x)=t-2 (i) What is the velocity and acceleration of the particle at t=0? (ii) When will the velocity of the particle become zero? (iii) What is the displacement of the particle when its velocity is zero? (iv) Is the motion of the particle uniformly accelerated or not?

Knowledge Check

  • The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t = sqrt(x) + 3 . The displacement of the particle when its velocity is zero will be.

    A
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    B
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    C
    zero
    D
    6 m

  • The relation 3t=sqrt(3x)+6 describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero is

    A
    24 metres
    B
    12 metres
    C
    5 metres
    D
    zero

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