An electric heater ofpower 1kW emits thermal radiations the surface area of heating element of heater is `200 cm^(2)`. If this heating element is treated like a black bodyfind the temperature at its surface. Assume its temperature is very much higher then its surroundings.

Explanation

To find the temperature at the surface of the electric heater, we can use the Stefan-Boltzmann law, which states that the power radiated by a black body is proportional to the fourth power of its absolute temperature. The formula is given by:

\[ P = \sigma A T^4 \]

Where:
- \( P \) = power (in watts)
- \( \sigma \) = Stefan-Boltzmann constant \( \approx 5.67 \times 10^{-8} \, \text{W/m}^2 \text{K}^4 \)
- \( A \) = surface area (in square meters)
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