Explain why the bond angle of `H _(2)O` is `104 .5^(@)` while that of `F _(2)O` is `102^(@).`
Text Solution
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The bond pair of electrons are drawn more towards F in `F_(2)O`, whereas in `H_(2)O` it is drawn towards O. So bp – bp repulsion in `H_(2)O` is greater than that in `F_(2)O`.
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