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Explain the following : Out of Sc^(3+)...

Explain the following :
Out of `Sc^(3+), Co^(2+)` and `Cr^(3+)` ions, only `Sc^(3+)` is colourless in aqueous solutions. (Atomic no. : Co = 27 Sc = 21 and Cr = 24)

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Explain the following : (a) Out of Sc^(3+), Co^(2+) " and "Cr^(3+) "ions, only "Sc^(3+) is colourless in aqueous solutions. (Atomic no.: Co =27, Sc = 21 and Cr =24) (b) The E^(@)Cu^(2+)//Cu for copper metal is positive (+0.34), unlike the remaining members of the first transition series. (c) La(OH)_(3) " is more basic than Lu "(OH)_(3).

Why is Sc^(3+) colourless ?

Knowledge Check

  • Which one of the following forms a colourless solution in aqueous medium ? (Atomic number : Sc =21, Ti = 22, V = 23 , and Cr = 24 )

    A
    `V^(3+)`
    B
    `Cr^(3+)`
    C
    `Ti^(3+)`
    D
    `Sc^(3+)`

  • Out of the following ions Ti^(3+), V^(3+), Cu^(+), Sc^(3+), Mn^(3+) and Co^(2+) the colourless ions will be

    A
    `Cu^(+), Sc^(3+)`
    B
    `Ti^(3+), V^(3+)`
    C
    `Cu^(+), Co^(2+)`
    D
    `Sc^(3+), Fe^(3+)`

  • The spin only magnetic of Cr^(3+) in aqueous solution would be :

    A
    `sqrt(3) B.M.`
    B
    `sqrt(15)B.M.`
    C
    `sqrt(8)B.M.`
    D
    `sqrt(35)B.M.`

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    Sc^(3+) is colourless is aqueous solution whereas Ti^(3+) is coloured.

    Out of Cr^(2+) and Cr^(3+) , which one is stable in aqueous solution ?

    Why is Sc^(3+) colourless while Ti^(3+) coloured? (Atomic number Sc = 21, Ti = 22)

    Of the ions Co^(2+), Sc^(3+) and Cr^(3+) which ones will give coloured aqueous solutions and how will each of them respond to a magnetic field and why?

    In which of the following paris both the ions are coloured in aqueous solution? (Atomic number, Sc - 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)

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