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How can you increase the reduction poten...

How can you increase the reduction potential of an electrode for the reaction :
`M^(n+)(aq)+n e^(-)rarrM(s)`

Text Solution

AI Generated Solution

To increase the reduction potential of an electrode for the reaction \( M^{n+}(aq) + n e^- \rightarrow M(s) \), we can follow these steps based on the Nernst equation. ### Step-by-Step Solution: 1. **Understand the Nernst Equation**: The Nernst equation is given by: \[ E = E^\circ - \frac{2.303RT}{nF} \log \left( \frac{[\text{Products}]}{[\text{Reactants}]} \right) ...
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Knowledge Check

  • Use the given standard reduction potentials to determine the reduction potential for this half-reactions. MnO_(4)^(-)(aq) + 3e^(-) + 4H^(+) rightarrow MnO_(2)(S) + 2H_(2)O(l)

    A
    1.695 V
    B
    2.825 V
    C
    3.389 V
    D
    5.086 V
  • Ag^(+)(aq) + e^(-) rightarrow Ag(s) E^(@) = 0.80V Co^(2+)(aq) + 2e(-) rightarrow Co(s) E^(@) = -0.28V Use the standard reduction potentials to determine the standard potential for the reaction: Co(s) + 2Ag^(+)(aq_) rightarrow Co^(2+)(aq) + 2Ag(s)

    A
    0.52V
    B
    0.66V
    C
    1.08V
    D
    1.88V
  • Using the above information, determine the standard reduction potential for the following reaction, 2M(s)+3Zn^(2+)(aq) rarr 2M^(3+)(aq)+3Zn(aq),E^@ = 0.90V Zn^(2+)(aq) +2e^(-) rarrZn(s) , E^@ = -0.76 V

    A
    `0.90 V`
    B
    `+1.66V`
    C
    `-0.62 V`
    D
    `-1.66 V`
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    Calculate the reduction potential for the following half cell reaction at 298 K. Ag^(+)(aq)+e^(-)toAg(s) "Given that" [Ag^(+)]=0.1 M and E^(@)=+0.80 V

    The standard electrode potential corresponding to the reaction : Au^(3+)(aq) +3e^(-) rarrAu(s) is 1.42 V . Predict (i) if gold can be can be dissolved in 1 M HCl solution and (ii) on passing hydrogen gas through gold solt solution, metallic gold will be precipitated or not .