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(a) Deduce the number of 3d electrons...

(a) Deduce the number of 3d electrons in the folloing ions :
`Cu^(2+) , Sc^(+3)`

Text Solution

AI Generated Solution

To determine the number of 3d electrons in the ions Cu²⁺ and Sc³⁺, we will first find the electronic configurations of the neutral atoms and then adjust for the ions. ### Step 1: Determine the electronic configuration of Cu (Copper) - The atomic number of copper (Cu) is 29. - The electronic configuration of Cu is: - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ ### Step 2: Determine the electronic configuration of Cu²⁺ ...
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Write down the number of 3d electrons in each of the following ions : Ti^(2+), V^(2+), Cr^(3+), Mn^(2+), Fe^(2+), Co^(2+), Ni^(2+) and Cu^(2+) . Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

Write down the number of 3d electrons in each of the following ions : Ti^(2+),V^(2+),Cr^(3+),Mn^(2+),Fe^(2+),Fe^(3+),Co^(2+),Ni^(2+) and Cu^(2+) Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

Knowledge Check

  • The number of unpaired electrons in Ce ^(3+) ion is 0

    A
    0
    B
    1
    C
    2
    D
    3
  • The number of unpaired electrons in Cr^(3+) ion is

    A
    3
    B
    5
    C
    4
    D
    1
  • The number of d-electrons in Fe ^(+2) ion is equal to that of

    A
    d-electrons in `Ni^(2+)`
    B
    d-electrons in `V^(2+)`
    C
    d-electrons in `CO^(3+)`
    D
    d-electrons in `Cr ^(+)`
  • Similar Questions

    Explore conceptually related problems

    Write down the number of 3d electrons in each of the folloowing ions : Ti^(2+),V^(2+), Cr^(3+), Mn^(2+), Fe^( 2+),Fe^(3+),Co^(2+),Ni^(2+) and Cu^(2+) Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions ( octahedral).

    Write down the number of 3d electrons in each of the following ions: Ti^(2+),V(2+), Cr^(3+),Mn^(2+), Fe^(2+),Fe^(3+),Co^(2+),Ni^(2+) " and " Cu^(2+) . Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

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