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In figure, P is the mid-point of side BC...

In figure, P is the mid-point of side BC of a parallelogram ABCD such that `angleBAP=angleDAP`. Prove that AD = 2CD. ltBrgt

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Explore conceptually related problems

In the given figure, P is the mid-point of side BC of a parallelogram ABCD such that angleBAP=angleDAP. Prove that AD = 2CD.

The mid-point of side CD of parallelogram ABCD is 'm' in the given figure what is the ratio ON : OB?

Knowledge Check

  • In the given figure, M is the mid-point of the side CD of the parallelogram ABCD. What is ON:OB?

    A
    `3:2`
    B
    `2:1`
    C
    `3:1`
    D
    `5:2`

  • In parallelogram ABCD, if P is the mid-point of side AB, then

    A
    DP bisects diagonal AC
    B
    DP bisects diagonal BD
    C
    DP trisects diagonal BD
    D
    DP trisects diagonal AC and trisected by AC

  • If P and Q are the middle points of the sides BC and CD of the parallelogram ABCD, then AP+AQ is equal to

    A
    AC
    B
    `(1)/(2)AC`
    C
    `(2)/(3)AC`
    D
    `(3)/(2)AC`

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    If D is the mid-point of the side BC of a triangle ABC, prove that vec AB+vec AC=2vec AD .

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    P is the mid-point of side AB of a parallelogram ABCD .A Line through B parallel to PD meets DC at Q and AD produced at R. Prove that ( i )AR=2BC (ii) BR=2BQ.

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    P is the mid-point of side AB of parallelogram ABCD. A line drawn from B parallel to PD meets CD at Q and AD produce at R. Prove that : (i) AR = 2BC (ii) BR= 2BQ

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