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HCF of 3^(3)xx5^(4) and 3^(4)xx5^(2) is ...

HCF of `3^(3)xx5^(4)` and `3^(4)xx5^(2)` is _______________.

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To find the HCF (Highest Common Factor) of the two numbers given in the question, we will follow these steps: ### Step 1: Identify the numbers The two numbers we need to find the HCF for are: 1. \( 3^3 \times 5^4 \) 2. \( 3^4 \times 5^2 \) ### Step 2: Factor the numbers We can express the numbers in their prime factorization: - The first number is \( 3^3 \) and \( 5^4 \). - The second number is \( 3^4 \) and \( 5^2 \). ### Step 3: Determine the HCF for each prime factor For the prime factor \( 3 \): - The powers are \( 3 \) (from the first number) and \( 4 \) (from the second number). - The HCF is the minimum of these powers: \( \min(3, 4) = 3 \). For the prime factor \( 5 \): - The powers are \( 4 \) (from the first number) and \( 2 \) (from the second number). - The HCF is the minimum of these powers: \( \min(4, 2) = 2 \). ### Step 4: Combine the HCFs of the prime factors Now, we combine the HCFs of the prime factors: \[ \text{HCF} = 3^{\min(3, 4)} \times 5^{\min(4, 2)} = 3^3 \times 5^2 \] ### Step 5: Write the final answer Thus, the HCF of \( 3^3 \times 5^4 \) and \( 3^4 \times 5^2 \) is: \[ 3^3 \times 5^2 \] ### Step 6: Calculate the numerical value (optional) If needed, we can calculate the numerical value: \[ 3^3 = 27 \quad \text{and} \quad 5^2 = 25 \] So, \[ 27 \times 25 = 675 \] ### Final Answer The HCF of \( 3^3 \times 5^4 \) and \( 3^4 \times 5^2 \) is \( 3^3 \times 5^2 \) or numerically \( 675 \). ---
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