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The K(alpha) line obtained for molybdenu...

The `K_(alpha)` line obtained for molybdenum `(Z = 42)` is 0.71 Å. Then, the wavelength of the `K_(alpha)` line of copper (Z = 29) is

A

`21.4Å`

B

`1.52Å`

C

`1.04Å`

D

`0.71Å`

Text Solution

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The correct Answer is:
B
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The wavelength of the characteristic X-ray K_(alpha) line emitted from Zine (Z = 30) is 1.415 Å . Find the wavelength of the K_(alpha) line emitted from molybdenum Z = 42) .

The wavelength of the K_(alpha) line for an element of atomic number 57 is lambda . What is the wavelength of the K_(alpha) line for the element of atomic number29 ?

Knowledge Check

  • The X - ray wavelength of L_(alpha) line of platinum (Z = 78) is 1.30 Å . The X - ray wavelength of L_(alpha) line of Molybdenum (Z = 42) is

    A
    `5.41 Å`
    B
    `4.20 Å`
    C
    `2.70 Å`
    D
    `1.35 Å`

  • The K_(alpha) line from molybdenum (atomic number=42) has a wavelength off .7078Å. The wavelength off K_(alpha) line of zinc (atomic number=30) will be

    A
    1Å
    B
    1.3872Å
    C
    0.3541Å
    D
    0.5Å

  • The wavelength of K_(alpha) line for an element of atomic number 43 is lambda . Then the wavelength of K_(alpha) line for an element of atomic number 29 is

    A
    `(43)/(29) lambda`
    B
    `(42)/(28) lambda`
    C
    `(9)/(4) lambda`
    D
    `(4)/(9) lambda`

    • Similar Questions

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    Find the wavlength of the K_(alpha) line in copper (Z=29) if the wavelength of the K_(alpha) line in iron (Z=26) is known to be equal to 193 p m .

    Find the wavelength of the K_(alpha) line in copper (Z=29) , if the wave length of the K_(alpha) line in iron (Z=26) is known to be equal to 193 "pm" (Take b=1 )

    The wavelength of K_(alpha) line for an elèment of atomic number 29 is lambda . The wavelength of K_(alpha) line for an element of atomic number 15 is beta lambda . Find beta . Take Moseley's constant, b=1 for both elements)

    In a Coolidge tube, the potential difference used to accelerate the electrons is increased from 24. 8 kV to 49.6 kV . As a result, the difference between the wavelength of K_(alpha) -line and minimum wavelength becomes two times. The initial wavelength of the K_(alpha) line is [Take (hc)/(e) = 12 .4 kV Å ]

    If lambda_(Cu) is the wavelength of K_(alpha) X-ray line of copper (atomic number 29 ) and lambda_(Mo) is the wavelength of the K_(alpha) X-ray line of molybdenum (atomic number 42 ),then the ratio lambda_(Cu)//lambda_(Mo) is close to

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